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The Monte Hall problem
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[QUOTE="Forloveoforange, post: 5081423, member: 1015"] Its the same game, so don't look at it as a new game. You just have to understand a couple things. You have to understand that your original choice is a group in itself, and it has the obvious odds that will stay with it, because it is the same game (1 out of 3). Do you understand that? Next, you have to understand that the remaining doors are 2 out of 3 odds, as a group. Do you understand that? The host shows that one door of the 2 is not it. But that door group keeps the same 2 out of 3 chance. So Door 2 keeps the same 2 out of 3 chance. I think this is the one that you are not understanding. It is the same group. It loses Door 3, but it is the same group. It is not a 100% chance, but it is 66 and 2/3 %, and it is because the host had to pick a blank door. The odds change because it was not a luck factor pick. This is why it stays a 3 door game, basically, because it is not a luck factor game. The doors have unequal value because they are picked differently due to formula. It is the original game. It doesn't change. The host in the know helps the informed contestant, as long as the contestant understands the original group values. So, I think you understand the game when you understand that the 2-door group stays at 2 out of 3 chance, and you know which specific door has that individual chance when the other door is taken away. [/QUOTE]
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