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The Monte Hall problem
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[QUOTE="Forloveoforange, post: 5083069, member: 1015"] If you understood the game, you would know why it doesn't change to a 2 door game. Aren't you just basically taking sets of 3 cards and looking at how they show up in order? So, what you do is, you take ANY one of the 3 cards and place it to the side. Next, you look at the other 2 cards. They will be either red and black or red and red. Now be like Monty Hall and place a red card face up to the side. This card is out of the game. So, NOW SWITCH to the other card you peeked at. That's it. You have effectively taken advantage of 2 cards. 2 cards, no matter what 2 cards, 2 cards at face value will ALWAYS have a 2/3 chance of having a black card in them. That is the Monty Hall scenario and you win a car unless your first choice was the car, which was a 1/3 chance. What if Monty didn't even show a goat? What if he just asked you to pick a 2nd door to add to your first? He would be giving you the same odds as what he did by showing a goat. The game could be random and you would still get the same high odds, since he let you choose 2 random doors. [/QUOTE]
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